Four long, parallel conductors carry equal currents of I = 6.27 A. The figure sh

Question

Four long, parallel conductors carry equal currents of I = 6.27 A. The figure shown below is an end view of the conductors. The direction of the current is into the page at points Aand B (indicated by the crosses) and out of the page at C and D (indicated by the dots). Calculate the magnitude and direction of the magnetic field at point P, located at the center of the square with edge of length 0.200 m.

magnitude     T direction     ---Select--- upward to the right out of the monitor to the left downward into the monitor

Explanation / Answer

Note that the magnitude of the magnetic field du to a long wire is

B = uo I / (2 pi r)

Thus, each of them produces a B field of magnitude

B = 4.433*10^-6 T

Using the right hand rule of the components of each,

B(A) = 4.433*10^-6 T <-1/sqrt(2), -1/sqrt(2)>
B(B) = 4.433*10^-6 T <1/sqrt(2), -1/sqrt(2)>
B(C) = 4.433*10^-6 T <1/sqrt(2), -1/sqrt(2)>
B(D) = 4.433*10^-6 T <-1/sqrt(2), -1/sqrt(2)>

Adding these four,

Bnet = 12.53 uT, to the left [ANSWER]

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