https://chip.physics.purdue.edu/protected/HallidayEMimg/h31p33.jpg A metal rod i
ID: 1399551 • Letter: H
Question
https://chip.physics.purdue.edu/protected/HallidayEMimg/h31p33.jpg
A metal rod is forced to move with constant velocity v along two parallel metal rails, connected with a strip of metal at one end, as shown in Figure below. A magnetic field B = 0.263 T points out of the page. The rails are separated by 16.3 cm and the speed of the rod is 48.3 cm/s. If the rod has a resistance of 15.8 ohms and the rails and connector have negligible resistance, what is the current in the rod?
a. zero
b. 2.62 mA
c. 5.59 mA
d. 1.31 mA
e. 7.87 mA
a. zero
b. 2.62 mA
c. 5.59 mA
d. 1.31 mA
e. 7.87 mA
Explanation / Answer
EMF = e = BvL
v = velocity = 48.3 cm/s = 48.3 x 10^-2 m/s
L = 16.3 cm = 16.3 x 10^-2 m
B = 0.263 T
e = 0.0207 V
I = e/R
I = 0.0207 / 15.8 = 1.31 x 10^-3 A
I = 1.31 mA
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