1) Using one of your heights and times from when the object was released to when
ID: 1399527 • Letter: 1
Question
1) Using one of your heights and times from when the object was released to when the object hits the floor, calculate g. (This is an experimental value of g)
2) Using all of you height data points, figure out how to make a linear graph of height and time. Determine the slope of the graph. This is related to your second experimental value of g. Determine your second experimental value of g.
3) compare both your experimental values of g to the theoritcal value.
4) What is the percentage difference btween your experimetal values of g and the accepted value, 9.81m/s2 ?
5) How do you account fo this difference?
6) Does the theoritcal value for g fall within the final error range (the uncertainity) of your experimental value?
7) Explain with the primary limitation on your data and how it can be corrected. What factor in the experiment had the biggest effect on collecting valid data and how would you make the experiment more accurate?
please answer all questions and show work
height time1 time2 time3 time4 avg time 2 m 0.45 s 0.43 s 0.35 s 0.36 s 0.39 s 1.8 m 0.4 s 0.5 s 0.48 s 0.42 s 0.38 s 1.4 m 0.41 s 0.36 s 0.37 s 0.33 s 0.37 s 1.1 m 0.37 s 0.33 s 0.33 s 0.40 s 0.36 sExplanation / Answer
1) When the object hits the ground the velocity will be equal to 0.
So initial velocoty=d/t=2/0.39=5.13 m/s
v=u-at
a=u/t=5.13 m/s/0.39=13.15 m/s2
b)Plot height along the y axis and time along the x axis
we will get a straight line. M
ark 2 points. Then find the slope.
For second value of g,
h=1.8 m and time t=0.38 s
final velocity=0 m/s
so v=u-gt
u=1.8/0.38=4.73 m/s
g=4.73 m/s/0.38=12.46 m/s2
c) Theorotical Value is 9.81 m/s2
Here we get in first case,g=13.15 m/s2
and second case,g=12.46 m/s2
4)V1 = 9.81 and V2 = 13.15
(( | V1 - V2 | / ((V1 + V2)/2) ) * 100
= ( | 9.81 - 13.15 | / ((9.81 + 13.15)/2) ) * 100
= ( | -3.34 | / (22.96/2) ) * 100
= ( 3.34 / 11.48 ) * 100
= 0.290941 * 100
= 29.0941% difference
V1 = 9.81 and V2 = 12.46
( | V1 - V2 | / ((V1 + V2)/2) ) * 100
= ( | 9.81 - 12.46 | / ((9.81 + 12.46)/2) ) * 100
= ( | -2.65 | / (22.27/2) ) * 100
= ( 2.65 / 11.135 ) * 100
= 0.237988 * 100 = 23.7988% difference
5) The accuracy is very low. Highly deviated from the original value
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.