A block is attached to a horizontal spring. On top of this block rests another b

Question

A block is attached to a horizontal spring. On top of this block rests another block. The two-block system slides back and forth in simple harmonic motion on a frictionless horizontal surface. At one extreme end of the oscillation cycle, when the blocks come to a momentary halt, the top block is lifted vertically upward, without disturbing the bottom block. What happens to the amplitude and the angular frequency of the ensuing motion?

The amplitude remains the same, and the angular frequency increases.

The amplitude increases, and the angular frequency remains the same.

Both the amplitude and the angular frequency increase.

Both the amplitude and the angular frequency decrease

Both the amplitude and the angular frequency remain the same.

Explanation / Answer

Here ,

as the angular frequency is given as

w = sqrt(k/m)

when the blocks are stationary , that is their maximum position , one of the blocks is lifted

as that time , there is no kinetic energy in the system , hence , no energy is lost

and the amplitude stays the same ,

Now, as the mass decreses , the anglular frequency increases .

Hence , The amplitude remains the same, and the angular frequency increases.

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