1. A light ray incident on a block of glass makes an incident angle of 50.0° wit

Question

1. A light ray incident on a block of glass makes an incident angle of 50.0° with the normal to the surface. The refracted ray in the block makes an 36.1° with the normal. What is the index of refraction of the glass?

2.

A light ray traveling from a higher index-of-refraction medium to the lower (for example, from water into air) would bend away from the normal. When the refracted ray is parallel to the boundary of the medium, 2 = 90°. The incident angle, 1, becomes c, called the

Explanation / Answer

1)

incident angle , i = 50 degree

refracted angle , r = 36.1 degree

Now, let the index of refraction is n

Using snell's law,

n1 * sin(i) = n * sin(r)

1 * sin(50) = n * sin(36.1)

solving for n

n = 1.30

the index of refraction of glass is 1.30

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