Help with this lab question please! The question refers to the experiment we did

Question

Help with this lab question please! The question refers to the experiment we did in lab where a steel ball is at the end of a ramp while an incoming ball comes down the ramp and hits the inital steel ball. These fall onto a piece of paper where their positions were marked.

A student at another university repeats the experiment you did In lab. Her target ball is 0.860 m above the floor when it is In the target holder and the steel ball she uses has a mass of 0.0120 kg. She finds that the target ball travels a distance of 1.40 m after it is struck. Assume g = 9.80 m/s2. What is the kinetic energy (in joules) of the target ball just after it is struck?

Explanation / Answer

here

If you assume that the ball is fired horizontally then there will be no vertical component. The horizontal range, HR = v * time

the time for the ball to reach the ground can be given by s = 1/2 gt^2
Here s is 0.86m
solving for t gives:-
t = sqrt [2s/g]
t = sqrt [(2 * 0.86)/9.8]
t = 0.4189 sec

HR
HR = v * time
v = HR / time
v = 1.4 / 0.4189
v = 3.342 m/s

KE = 0.5 mv^2
KE = 0.5 * 0.0120 * 3.342^2
KE =0.0670 J

so the kinetic energy of the target ball just before it is struck is 0.0670 J

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