-A piece of aluminum wire with circular cross section has resistivity p. If the

Question

-A piece of aluminum wire with circular cross section has resistivity p. If the diameter of the cross section is 2mm and length is 20 cm. what is the resistance of that sample? A) 15924 B) 127388 C) 52003 D) 63662 E) 10000. -Electric force between 2 equal positive charges is 1 N. If the separation between the charges is 1m, what is the magnitude of each charge? A) 1sqrt kC. B) 0.1sqrt K. c) 2sqrt3K C. d) 10K C. E) 0.01sqrt k C -A piece of aluminum wire with circular cross section has resistivity p. If the diameter of the cross section is 2mm and length is 20 cm. what is the resistance of that sample? A) 15924 B) 127388 C) 52003 D) 63662 E) 10000. -Electric force between 2 equal positive charges is 1 N. If the separation between the charges is 1m, what is the magnitude of each charge? A) 1sqrt kC. B) 0.1sqrt K. c) 2sqrt3K C. d) 10K C. E) 0.01sqrt k C

Explanation / Answer

here by using the formula

R = rho * L / A

rho = resistivity of aluminium = 2.65 * 10^-8 ohm m

R = rho * L / pie *r^2

R = 2.65 *10^-8 * 0.2 / 3.14 * 0.001^2

R = 0.00168789 ohm

the resistanc of the wire is 0.00168789 ohm

then the second question

using the formula

F = k * q * q / r^2

1 = kq^2 /r^2

1 = k *q^2 / 1

q = sqrt(1/k)

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