last attempt please help! The Hubble Space Telescope has a mirror diameter of 2.

Question

last attempt please help!

The Hubble Space Telescope has a mirror diameter of 2.4 m. Suppose the telescope is used to photograph stars near the center of our galaxy, 30,000 light years away, using red light with a wavelength of 730 nm .

Part A

What's the distance (in km) between two stars that are marginally resolved? The resolution of a reflecting telescope is calculated exactly the same as for a refracting telescope.

Express your answer using two significant figures.

Part B

For comparison, what is this distance as a multiple of the distance of Jupiter from the sun?

Express your answer using two significant figures.

Explanation / Answer

first we will use the formula

theta= 1.22 lambda / D

lamda = 730 * 10 ^ -9

D=2.4 m

theta = (1.22) * (730 * 10 ^ -9) /2.4

theta = 3.710834 * 10 ^ -7

theta=Y/(30000 light years *9.4605284 × 10^12 kilometers)

Y = 10.53 * 10 ^ 10 km --------------------------------->>>>>>>>>> answer )

part 2 ) now we can divide the answer Y from part 1 ) to the average distance of jupiter to the sun(778,412,010) = 135       --------------------------------------->>>>>>>>>>>>> answer )

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