determine the width of the slit, D. Figure 4 shows the setup for a single slit d

Question

determine the width of the slit, D. Figure 4 shows the setup for a single slit diffraction pattern. In class you learn that for a single slit, the intensity minimum occurs when Dain nA where and is the number of minima from the central maximum. Intensity Figure 4 Diffraction of a single slit. Comparing Figure 4 with Figure 2, one can draw the conclusion that the double slit fringe pattern is actually composed of two effects, the interference between the light sources from the two slits and the diffraction pattern from each slit. Since the slits are very close to each other, the diffraction pattern from each slit superimposes each other. 65 66 67 68 69 70 Figure 5 Diffraction pattern from a single slit. The next two parts will make use of Figure 5. (indicated by the black arrow) to the first minimum (middle of the whi area)? IThis distance is What is the distance from the central y in Figure 4.) 1.42 cm You are correct. Computer's answer now shown above. Previous Tries Your receipt no. is 161-9579 Use the equation for a single slit, calculate the width, D of the slit. The distance from the slit to the screen, Lis kept at 2.02 m. The angle e can be calculated by using Figure 4 Submit Answer Incorrect. Tries 9/15 Previous Tries Math

Explanation / Answer

given,

distance between slit and screen L=2.02 m

distance between central maximum and fisrtst minimum,y=1.42 cm

wave length , lambda=6.45*10^-7 m

let width of the slit is, D

use,

D*sin(theta)=n*lambda

here

sin(theta)=y/L

now,

D=n*lambda/sin(theta)

=1*6.45*10^-7*L/y

=1*6.45*10^-7*2.02/1.42*10^-2

=91.75*10^-6 m

=91.75 um

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