7 . A 660 g piece of copper is heated in a furnace to a temperature T . The copp

Question

7. A 660 g piece of copper is heated in a furnace to a temperature T. The copper is then inserted into a 180 g copper calorimeter containing 285 g of water. The initial temperature of the water and calorimeter is 16 °C, and the final temperature after equilibrium is established is 37 °C. When the calorimeter and its contents are weighed, 38.0 g of water are found to have evaporated. What was the temperature T?(cw = 4186 J/(kg.°C), Lf=3.35 × 105 J/kg, Lv=2.26 ×106 J/kg, ccopper = 387 J/(kg.°C)

THEANSWER IVE BEEN GETTING IS WRONG PLEASE HELP

Explanation / Answer

Here ,

mass of water left , mW = 285 - 38

mW = 247 gm

mass of copper , mC = 660 gm

mass of calorimeter , mc = 180 gm

Now,

heat lost by copper piece = heat gain by water and calorimeter

mC*Ccu *(T - 37) = mW * Cw (37 - 16) + mc * Ccu *(37 - 16) + 38 * Lv

660 *(0.387) *(T - 37) = 247 * 4.186 * 21 + 180 * 0.387 * 21 + 38 *( (100 - 16)* 4.186 + 2.26 *20^3)

solving for T

T = 2870 degree C

the initial temperature of copper was 2870 degree C

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