1. Three collisions: a) Totally Inelastic collision: A 10-grams bullet is shot a

Question

1. Three collisions: a) Totally Inelastic collision: A 10-grams bullet is shot at a 2.0-kg wooden block and remains embedded in the block: Initially, the bullet and the block were moving towards each other as shown in the sketch below. Find the velocity ofthe block- bullet system right after the impact and calculate the fraction of the initial kinetic energy that is lost during collision 200 Mts b) Partially Inelastic collision: A 20 grams bullet is shot at a 400-grams hard stone Initially, the bullet and the block were moving towards each other as shown in the sketch below (the collision takes place above the ground). It is observed that right after the collision, the bullet is deflected upwards, perpendicular to its initial direction of motion, and with a third of its initial speed. Find the stone's speed and direction of motion right after the collision, and calculate the fraction of the initial kinetic energy that is lost during collision mls o c) Elastic collision: Two rubber balls (one of 200 grams mass and the other 300 grams) collide elastically head-on. Before the collision, they were moving as shown in the sketch below. Find the speed and direction of motion for each ball right after collision. (t0 pts) 12 m/s 200 2000

Explanation / Answer

let the velocity after the collision is u m/s

Now, using conservation of momentum

-200 *0.010 + 2 * 15 = (2 + 0.010)* u

u = 13.93 m/s

the final speed is 13.93 m/s in the direction of block.

Now,

fraction of kinetic energy lost = 1 - (0.5 * 2.01 * 13.93^2)/(0.5 * 200^2 * 0.010 + 0.5 * 2 * 15^2)

fraction of kinetic energy lost = 0.541

the fraction of kinetic energy lost is 0.541

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