1. When the charge on the plates of a capacitor is doubled. the magnitude of the

Question

1. When the charge on the plates of a capacitor is doubled. the magnitude of the electric potential difference across the capacitor a) s doubled b) is halved c) remains the same d) quadrupled. 2. If a charge is moving with uniform velocity, v, under the combined influence of an electric field, E. and a magnetic field, B, then: a) is parallel to the B-field b) must be perpendicular to the B-field. c) must be perpendicular to the E-field. d) the E- and B- fields are anti-parallel to each other. (Bold face indicates vector quantities.)

Explanation / Answer

1)q=cv

c=epsilon x area/length

q doubles then v doubles

option A

2)F = q(E + v x B) where all but charge are vectors.

so v is pependicular B

option B

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