Water flows through a garden hose. At one point in the hose where the cross-sect

Question

Water flows through a garden hose. At one point in the hose where the cross-sectional area is 3.56 *10^-4 m^2 the velocity of the water is 0.718 m/s. The nozzle at the end of the hose decreases the cross-sectional area to half of what it is in the rest of the hose. Assume that the density of the water remains constant.

1. What is the cross-sectional area of the nozzle?

2. What is the velocity of the water as it goes through the nozzle?

Water flows through a garden hose. At one point in the hose where the cross-sectional area is 3.56 *10^-4 m^2 the velocity of the water is 0.718 m/s. The nozzle at the end of the hose decreases the cross-sectional area to half of what it is in the rest of the hose. Assume that the density of the water remains constant.

1. What is the cross-sectional area of the nozzle?

2. What is the velocity of the water as it goes through the nozzle?

Explanation / Answer

1)

Given that A1 = 3.56*10^-4 m^2

v1 = 0.718 m/s

A2 = ?

But given that A = A1/2 = (3.56*10^-4)/2 = 1.78*10^-4 m^2

2) From equation of continuty

A1*v1 = A2*v2

A1 *v1 = (A1/2)*v2

v2 = 2*v1 = 2*0.718 = 1.436 m/s

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