A capacitor is being charged from a battery and through a resistor of 10 kohms.

Question

A capacitor is being charged from a battery and through a resistor of 10 kohms. It is observed that the voltage on the capacitor rises to 80% of its maximal value in 4 seconds. Calculate the capacitor's capacitance A capacitor is being charged from a battery and through a resistor of 10 kohms. It is observed that the voltage on the capacitor rises to 80% of its maximal value in 4 seconds. Calculate the capacitor's capacitance A capacitor is being charged from a battery and through a resistor of 10 kohms. It is observed that the voltage on the capacitor rises to 80% of its maximal value in 4 seconds. Calculate the capacitor's capacitance

Explanation / Answer

since the voltage on the capacitor is raising.surely this will be a case of charging of RC circuit

time constant T = R*C

the using formula is e = V*(1-e^(-t/T))

0.8*V = V* (1-e^(-4/T))

0.8 = 1-e^(-4/T)

e^(-4/T) = 0.2

-4/T = ln(0.2)= -1.069

T = 4/1.069 = 2.5 S

R*C = 2.5

Capacitance C = 2.5/R = 2.5/10000 = 25*10^-4 F= 2500 uF

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