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The labeled graphs below represent the upward trajectories of 4 bodies, two slid

ID: 1395552 • Letter: T

Question

The labeled graphs below represent the upward trajectories of 4 bodies, two sliding upwards on frictionless inclines and two in free flight. Note that all 4 bodies reach the same maximum height (9 meters) after traveling from the same initial elevation (0 m).

The choices are GREATER THAN, LESS THAN, or EQUAL TO

1. The initial speed of P is _______ that of Q

2. The time of travel of P is ______ that of R

3. The time of travel of P is _______ that of N

4. The initial speed of R is ________ that of P

5. The time of travel of Q is _______ that of N

6. The initial speed of Q is ________ that of N

Explanation / Answer

2)

greater than

Because they have the same average velocity (as each experiences uniform acceleration) but P has further to go

4)

equal to

As explained above - they have the same initial kinetic energy.

6)

greater than

They have the same vertical velocity component but N has a smaller horizontal component as explained above.So the initial speed (magnitude of initial velocity) of N is smaller than R's

5)

the time travel of Q is equal to that of N

1)

the initial spped of P is greater than Q

3)

greater than

The time of travel for N is the time to reach max height. Considering vertical motion only, since h =

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