1. A certain length of wire carrying a current of 7.68 A is oriented horizontall

Question

1. A certain length of wire carrying a current of 7.68 A is oriented horizontally in a region where the earth's magnetic field has a dip angle of 55.0 degrees and a strength of 10STthe magnetic force on the wire is 1.45x10 N, Find the length of the wire. iagram requred ry 2. A long, straight wire is tangent to a circular insulated conductor (insulation of negligible thickness). If the diameter of the loop is 9.10 cm and both conductors carry currents pf 6.25 A (you choose the directions), find the magnitude of the net magnetic field at the center of the loo Diagron reaaive ld at the center offuothos) find the magnitude of the net 3. A particle of a given charge is moving at an angle of 15.0 degrees to a magnetic field and experiences a force of 6.25 mN. If this particle had triple the charge and were to move at double the speed and triple the angle between its velocity and the same magnetic field, what would be the magnetic force that the charge would experience? Diaaram Diagram reauivel

Explanation / Answer

1)

current in the wire , I = 7.68 A

theta = 55 degree

B = 4.98 *10^-5 T

F = 1.45 *10^-4 N

let the length of the wire is L

Now,

B*I*L *sin(theta) = force

4.98 *10^-5 * 7.68 * L * sin(55) = 1.45 *10^-4

solving for L

L = 0.463 m

the length of wire is 0.463 m

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