Question 3 4WileyPLUS xC Chegg.com N Netflix -> Dedugen.w.leyplus.com/edugen/stu

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Question 3

4WileyPLUS xC Chegg.com N Netflix -> Dedugen.w.leyplus.com/edugen/student/mainfr.uni :: Apps Facebook() FGCU Canvas Eagle Mail t Tumblr M Yahoo Home Read, Study & Practice x g Goodreads! We Are the (K DeviantArt YouTube W Wikipedia Wiley Plus N Netflix g GoodReads Box Nature Is Speaking Other bookmarks Assignment Gradebook AssignmentOpen Assignment MESSAGE MY INSTRUCTOR FULL SCREEN PRINTER VERSION BACK NEXT ASSIGNMENT RESOURCES Chapter 04, Problem 060 GO The drawing shows a circus clown who weighs 800 N. The coefficient of static friction between the clown's feet and the ground is 0.600. He pulls vertically downward on a rope that passes around three pulleys and is tied around his feet. What is the minimum pulling force that the clown must exert to yank his feet out from under himself? 054 057 Chapter 04, Problem 060 GO 062 hapter 04 064 GO 04 067 070 074 hapter 04 hapter 04 the tolerance is +/-2% eview Scor Review Results Study Objectiv Click if you would like to Show Work for this question: en SHOW HINT GO TUTORIAL SHOW SOLUTION LINK TO TEXT LINK TO TEXT 10:40 PM 6/19/2015

Explanation / Answer

Here ,

let the force of pulling is P ,

Normal force at the ground is N ,

balancing the force is

N = W - P

N = 800 - P

Now, for the feet to sweep ,

P = u*N

P = 0.6 *(800 - P)

1.6 P = 0.6 * 800

P = 300 N

the minimum pulling force is 300 N

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