A 3.00 kg stone is sliding to the right on a frictionless horizontal surface at

Question

A 3.00 kg stone is sliding to the right on a frictionless horizontal surface at 6.00 m/s when it is suddenly struck by an object that exerts a large horizontal force on it for a short period of time. The graph in the figure(Figure 1) shows the magnitude of this force as a function of time.

Just after the force stops acting, find the magnitude of the stone's velocity if the force acts to the right

. Just after the force stops acting, find the magnitude of the stone's velocity if the force acts to the left

Explanation / Answer

impulse area under the F , t graph

therefore from the graph

impulse = J = F*(t2-t1) = 2.5*1000*(16-15)*10^-3 = 2.5 Ns

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a = F/m = +2500/3 = 833.33 m/s^2

v = u+a*dt = 6+(833.33*1*10^-3) = 6.833 m/s

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if F is towards left

a = -F/m = -833.33 m/s^3

V= u+a*dt = 6-(833.33*1*10^-3) = 5.167 m/s

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