This question is from the lab \"Ohm\'s Law: Ohmic and Nonohmic Circuit Elements.

Question

This question is from the lab "Ohm's Law: Ohmic and Nonohmic Circuit Elements." (General Physics 2)

Any help will be much appreciated. Thank you!!

2. In Figure 3, the ammeter is measuring the current passing through the resistor only, but the voltmeter is measuring the total voltage across the resistance and the ammeter. If the resistance of the ammeter RA is one hundredth of R, what is the percent error when we calculate R' V/I using the voltage measured by the voltmeter in Figure 3? I Figure 3

Explanation / Answer

Here the ideal(when resistance of ammeter = 0)

voltage across resistance would be V and current would be I. but the presence of ammeter with some resistance in series with resistance causes some error.

total resistance of fig 3. is

R/100 + R =1.01R

Current through circuit = V/1.01R

SO actual R= V/(V/1.01R)=1.01R

therefore percentage error= (1.01R-R)/1.01R * 100%=0.99% error

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