1) A fairground ride spins its occupants inside a flying saucer-shaped container
ID: 1393306 • Letter: 1
Question
1) A fairground ride spins its occupants inside a flying saucer-shaped container.
a) If the horizontal circular path the riders follow has an 8.5 m radius, at how many revolutions per minute will the riders be subjected to a centripetal acceleration 1.6 times that due to gravity.?
2. An athlethe crosses 24m river by swimming perpendicu;ar to the water at a speed of 1 m/s relative to the water. He reaches the opposite side at a distance 45m downstream from his starting point.
w=24m
d=45m
Vs=1 m/s
Part a) How fast is the water in the river flowing with respect to the ground in m/s?
Part b) What is the speed ofthe swimmer with respect to a friend at rest on ground in m/s?
Explanation / Answer
1)
a) we know, centripetal acceration, a_rad = r*w^2
w = sqrt(a_rad/r)
= sqrt(1.6*g/r)
= sqrt(1.6*9.8/8.5)
= 1.358 rad/s
= 1.358*60/(2*pi)
= 12.98 revolution/minute <<<<---------Answer
2) from the given data
time taken to cross the river, t = W/Vs = 24/1 = 24 s
a) velocity of river, Vr = d/t
= 45/24
= 1.875 m/s <<<<---------Answer
b) relative speed of swimmer with respect to ground = sqrt(Vs^2 + Vr^2)
= sqrt(1^2 + 1.875^2)
= 2.125 m/s <<<<---------Answer
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