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iPad 6:55 PM webassign net My Notes o Ask Your Teacher 8. 0/5.88 points I Previous Answers SerPOP5 29. P.007 A photon with energy 2.90 eV is absorbed by a hydrogen atom (a) Find the minimum n for a hydrogen atom that can be ionized by such a photon. Your response differs from the correct answer by more than 10%. Double check your calculations (b) Find the speed of the electron released from the state in part (a) when it is far from the nucleus 1.09366 X Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully km/s Need Help? Read It 9. C+ -l points SerPOP5 29.P. 019 15.88 My Notes Ask Your Teacher Calculate the magnitude of the orbital angular momentum for a hydrogen atom in the following states (a) 3p J s (b) 2p J s Need Help? Read ItExplanation / Answer
energy of photon = Ep = 2.90 eV
ionization energy is given as ::
En = 13.6 /n2
at n = 1 , En = 13.6 eV > Ep hence will not ionize
at n = 2 , En = 3.4 eV > Ep hence will not ionize
at n=3 , En = 1.51 eV < Ep hence will ionize
so n = 3
b)
energy of photon = ionization energy + kinetic energy
2.90 eV = 1.51 eV + KE
KE = 1.39 eV
KE = 1.39 x 1.6 x 10-19
(0.5) m v2 = 2.22 x 10-19
(0.5) (9.1 x 10-31) v2 = 2.22 x 10-19
v = 6.985 x 105 m/s
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