A helicopter is lifting off from the ground and is moving vertically upward. The
ID: 1393193 • Letter: A
Question
A helicopter is lifting off from the ground and is moving vertically upward. The graph shows its vertical velocity vy versus time. How high is the helicopter after 12.0 s have elapsed?
xC Chegg.com N Netflix -> :: Apps [y] WileyPLUS × Dedugen.w.leyplus.com/edugen/student/mainfr.uni Facebook ,FGCU Canvas p Eagle Mail @ Tumblr M Yahoo DeviantArt YouTube W Wikipedia WileyPlus N Netflix g GoodReads Box Naturels Speaking Other bookmarks AssignmentOpen Assignment MESSAGE MY INSTRUCTOR FULL SCREEN PRINTER VERSION BACK NEXT ASSIGNMENT RESOURCES Chapter 02, Problem X07 A helicopter is lifting off from the ground and is moving vertically upward. The graph shows its vertical velocity vy versus time. How high is the helicopter after 12.0 s have elapsed? HW #1 +6.0 +3.0 0 0 2.0 4.0 6.0 8.0 10.0 12.0 t (s) Number the tolerance is +/-290 Click if you would like to Show Work for this question: nits Sho LINK TO TEXT Chapter Question Attempts: 0 of 3 used SAVE FOR LATER SUBMIT ANSWER All Rights Reserved. A Division of Version 4.14.0.5 11:40 PM 5/29/2015Explanation / Answer
Height = area of velocity vs time curve
H = (1/2)*2*6 + 4*6 + (1/2)*6*6 = 6 + 24 + 18 = 48 m
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