1. A 50.0kg object is pushed by you on a level table.The acceleration is 1.00m/s

Question

1. A 50.0kg object is pushed by you on a level table.The acceleration is 1.00m/s2. The opposing frictional force on the object is 200N. What force must you apply to accelerate the object as described?

The answer is 250 N, but I don't understand how they got that answer.

2. You, a typical physics student of mass 75.0kg, are standing on a scale in an elevator whose cable has been cut. The partially working emergency brakes allow the elevator to accelerate toward the ground at 2.45m/s2. What is the reading on the scale beneath your feet is? (Not the same as the net force acting on you)

The answer is 551.3 N, but I calculated 555N with this formula T=mg-ma. Was I wrong?

Help please!!!

Explanation / Answer

1)

Here ,

m = 50 Kg ,

a = 1 m/s^2

f = 200 N

let the applied force is F ,

using second law of motion ,

F - f = m*a

F - 200 = 50 * 1

F = 250 N

the force acting on the object is 250 N

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