There is a region with a constant magnetic field 4.8mT . The magnetic field is d

Question

There is a region with a constant magnetic field 4.8mT . The magnetic field is directed into the page. An open loop of wire is placed in the magnetic field. There is a conducting rod that has one end fixed at the center of the loop and the other end touching the open loop of wire. The rod rotates around the loop at a rate of 20.1rad/s . The length of the rod is 0.591m . The resistance of the loop is negligible and the rod is 8.9? . See the image below.

Part A

What is the emf induced in the rod?

Part B

What is the current induced in the rod?

Part C

What is the average electrical energy dissipated in the rod?

Explanation / Answer

Here,

emf = (1/2) B L^2 w

Thus,

emf = 0.016849 V or 16.849 mV   [ANSWER]

*****************

Thus,

I = emf /R = 1.893*10^-3 A or 1.893 mA   [ANSWER]

******************

Thus,

P = I^2 R = 3.19*10^-5 W   [ANSWER]

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