FFTFFTT FFFTTFT FFFTTFF FTFTFFT FFFTFFT TFFTFFT FFFTFFF In the picture below, th

Question

FFTFFTT

FFFTTFT

FFFTTFF

FTFTFFT

FFFTFFT

TFFTFFT

FFFTFFF

In the picture below, the two wires carry current I1 and I2, respectively, with positive current to the right. The charge q is positive and has velocity v to the right. If I2 = 0 and I1 is greater then zero, then the force on q is north. If I2 = 0 and I1 is greater then zero, then the magnetic field near charge q point out of the page. If I1 = 0 and I2 is greater then zero, then the force on q point out of the page. If v = 0, then the force on q is zero. If I1 is greater than I2, then the force on q in north. If I2 = -I1 then the force on q equals zero. If I1 = -I2 then the force on q equals zero. Incorrect. Tries 8/10 Previous Tries

Explanation / Answer

As q is a positive charge, then we use the right hand rule.

Note that we can determine the direction of the magnetic field due to the wires using the right hand rule.

1. TRUE. B is into the page. Thus, F is due NORTH.
2. FALSE. Into the page.
3. FALSE. B is the one that is out of the page.
4. TRUE.
5. TRUE. This is similar with number 1.
6. FALSE. The magnetic field at the middle even becomes stronger in this case, and hence the force.
7. TRUE. Wires of opposite currents repel.

So, it is TFFTTFT.

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