A child is riding a merry-go-round which completes one revolution every 8 36 s.

Question

A child is riding a merry-go-round which completes one revolution every 8 36 s. The child is standing 4 65 m from the center of the merry-go-round What is the magnitude of the centripetal acceleration of the child? 6 84 m/s2 3 94 m/s2 2 63 m/s2 0 0664 m/s2 A child pulls a 3.00-kg sled across level ground with a force of 5.00 N The massless rope makes an angle 30 0 degree above horizontal and the box is moving with a constant velocity What is the coefficient of friction between the sled and the ground? 0 161 0 188 0 0441 0 0851

Explanation / Answer

13. Solution

a = w2r; w= 2pi rad /8.36 s = 0.7516 rad/sec

r= 4.65m

a = (0.7516)2)(4.65)

= 2.63m/s2 ----->(c)

14. Ff = (us)(FN)

FN = (Fw - Fex)

FW = (mg) = 3*9.8 = 29.4N

Fex = Fsinx = 5 (sin30) = 2.5N

FN = (29.4 - 2.5) = 26.9N

Ff = 5cos30 = 4.33N

us = 4.33/26.9 = 0.161 ----> (a)

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