thin lens questions please show work. thank you! You have a converging thin lens
ID: 1390404 • Letter: T
Question
thin lens questions please show work. thank you!
Explanation / Answer
Note that
1/f = 1/do + 1/di
where
f = focal length = 30 cm
do = object distance = 3.50E+01 cm
di = image distance
Thus, solving for di,
di = 210 cm [ANSWER, PART A]
Thus, the magnification, m = -di/do,
m = -6
Thus, for the mirror,
Note that
1/f = 1/do + 1/di
where
f = focal length = -50 cm
do = object distance = -1.00E+01 cm
di = image distance
Thus, solving for di,
di = 12.5 cm [ANSWER, PART B, REAL, as di > 0]
Thus, the magnification, m = -di/do,
m = 1.25
Thus, the overall magnification is
mtot = m1 m2 = -6 (1.25)
mtot = -7.5 [ANSWER, INVERTED as mtot < 0, PART C]
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