answer questions 5 and 6 explain 5. A 40 N crate rests on a rough horizontal flo
ID: 1390385 • Letter: A
Question
answer questions 5 and 6 explain
Explanation / Answer
Weight of crate, W= mg = 40 N
So, m = 40/g = 40/9.8 = 4.08 kg
Minimum force required to move the body, F_min = us*m*g = 0.5*4.08*9.8 = 19.99 N
But applied force = 12 N
So, the body wont move and thus the frction must be equal and opposite to the applied force ,
So, friction = 12 N <------------answer
2)
W = mg = 6000
So, m = 6000/9.8 = 612.2 kg
Now, friction, f = uk*m*g = 0.05*612.2*9.8 = 300 N
As the equipment moves with constant velocity , thus the net force must be 0
Thus the applied force must be equal and opposite to friction
So, applied force = 300 N
So, work done by campers = F*d
where d = distance traveled = 1000 m
So, Work done = 300*1000 = 3*10^5 J <--------answer
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