A 10-cm-diameter circular loop of wire is placed in a 0.84-T magnetic field. Par

ID: 1390026 • Letter: A

Question

A 10-cm-diameter circular loop of wire is placed in a 0.84-T magnetic field.

Part A

When the plane of the loop is perpendicular to the field lines, what is the magnetic flux through the loop?

Express your answer to two significant figures and include the appropriate units.

?B = Wb

Part B

The plane of the loop is rotated until it makes a 40? angle with the field lines. What is the angle in the equation ?B = BAcos? for this situation?

Express your answer using two significant figures.

Part C

What is the magnetic flux through the loop at this angle?

Express your answer to two significant figures and include the appropriate units.

?B = Wb

Let we take flux as F and magnetic field B , area of loop A

given B=0.84T ,diameter=10cm,

radius=diameter/2

=5cm

a))

Since magnetic filed is perpendicular to plane of loop angle theta=0

A = pi x (0.05)2 =7.85x10-3

F = B x A x cos(0)

=6.5934x10-3Wb

b))

theta is the angle between the perpendicular to the loop,

so theta = 90-40 = 50 degrees in the given equation

c))

F=BxAxcos(50)

=0.84x7.85x10-3x0.64

=4.45x10-3Wb

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.