location in a conservative force field? A 0.20 m radius automobile tire starts t
ID: 1389537 • Letter: L
Question
location in a conservative force field? A 0.20 m radius automobile tire starts to rotate from rest and it is accelerating at a constant angular acceleration of 2.0 rad/s2. What is the centripetal acceleration of a point on the outer edge of the tire after 5.0 s? The orbits of the planets are Zeroth law of thermodynamics states that if two object A and B are separately in thermal equilibrium with a third object, then An object has 35 degree C temperature. What is its temperature in Fahrenheit? A metal rod has the initial length of 30 cm. at 20 degree C. When we increases its temperature to 95 degree C, its length becomes 30.08 cm. What is the coefficient of linear expansion? A rock, released at rest from the top of a tower, his the ground after 5.0s. What is the speed of the rock as it hits the ground? Vector A is 7.0 units in length and points along the positive x-axis; vector B is 4.0 units in length and points along a direction 45 degree from the positive x-axis. What is the magnitude of the resultant when vectors A and B are added?Explanation / Answer
11)
here ,
radius , r = 0.20 m
constant acceleration ,a = 2 rad/s^2
Now, after 5 s
angular speed , w = a*t
w = 5 * 2
w = 10 rad/s
Now,
centripetal acceleration , ac = w^2 * r
centripetal acceleration , ac = 10^2 * 0.20
centripetal acceleration , ac = 20 m/s^2
the centripetal acceleration of the point is 20 m/s^2
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