A 0.372m long metal bar is pulled to the left by an applied force F . The bar ri

Question

A 0.372m long metal bar is pulled to the left by an applied force F . The bar rides on parallel metal rails connected through a 44.5? resistor, as shown in the following figure(Figure 1) , so the apparatus makes a complete circuit. You can ignore the resistance of the bar and rails. The circuit is in a uniform 0.621T magnetic field that is directed out of the plane of the figure.

Part A

At the instant when the bar is moving to the left at 5.90m/s , what is the rate at which the applied force is doing work on the bar?

answer :

P= ( ) w

Explanation / Answer

the rate of doing work is called as power p

power p = V^2/R

here V is the induce emf

V = B*L*v

here given B is magnetic field = 0.621 T

L is the length of the rod = 0.372 m
v is the speed of the rod = 5.9 m/s

then V = 0.621*0.372*5.9 = 1.36 V

and R is the resistance = 44.5 ohm

power P = V^2/R = 1.36^2/44.5 = 0.0415 W

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