Please provide explanation or reasoning. 6. A wire with circular cross-section a

Question

Please provide explanation or reasoning.

6. A wire with circular cross-section and radius R is surrounded by another wire to form a coaxial cable- The outer wire is an annulus with inner radius R and outer radius 2R, so that there is no gap between the inner and outer wire. The inner wire carries a current of 10A and the outer wire carries a current of 10A in the opposite direction. What is the magnetic field strength at a distance of 3R from the centre of the cable if the magnetic field at a distance R from the centre is denoted by X? X/2 4X 2X Zero

Explanation / Answer

Here ,

the net current in the loop for radius 3R

current , I = 10 - 10

I = 0 A

,, Now, the magnetic field strength is

B = u0*(10 - 10)/(2*3.141 * 3 R)

B = 0 T

the magnetic field strength is 0 T

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