15. Circle your answers: (a) If we have a mass on a spring and a simple pendulum

Question

15. Circle your answers: (a) If we have a mass on a spring and a simple pendulum in an elevator and the elevator is accelerating downwards then the period of the spring will (increase, decrease, not change). (b) The period of the pendulum will (increase, decrease, not change). (c) Likewise the frequency of the spring will (increase, decrease, not change) and the frequency of the pendulum will (increase, decrease, not change). (d) If we decrease the mass on the spring by a factor of 25 then its frequency will (increase, decrease, not change) by a factor of __________ (put N/A if not changed). (e) If we decrease the mass on the pendulum by a factor of 25 then its frequency of the pendulum will (increase, decrease, not change) b a factor of _________ (put N/A if not changed). 16. (a) To open a certain classroom door requires Sammy to push on it with a minimum force perpendicular to the door of 4.50 N. If Sammy is pushing at 0.755 m from the hinges then what is the minimum torque required to open the door? (b) If Bobby pushes at the same point on the door as Sammy did but he pushes at a 60.0 degree angle WRT to the plane of the door then what force will he have to apply to open the door?

Explanation / Answer

15)

a) not change

b) increases

c) not change ....... decrease

d) increase by a factor of 5

e) not change

16)

a) Torque, T = R*F*sin(theta)

= 0.755*4.5*sin(90)

= 3.3975 N.m <<<<<<<<---------------Answer

b) Let F is the force.

T = R*F*sin(theta)

3.3975 = 0.755*F*sin(60)

==> F = 3.3975/(0.755*sin(60))

= 5.196 N <<<<<<<<---------------Answer

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.