In one of those very dark nights. Nerdeinstein aimed his flashlight at a pond at

Question

In one of those very dark nights. Nerdeinstein aimed his flashlight at a pond at Brewster?s angle. Using a light meter. he measured that the reflected light intensity is 50 Cd a) What is in Cd the intensity reading on the meter when a single ideal polarizer is inserted between the pond and the meter with the axis of the polarization of the polarizer perpendicular to the horizontal (pond surface)? b) What is in Cd the intensity reading on the meter when a second polarizer is placed between the first and the meter with their axis of polarization perpendicular to each other (the first polarizer is still perpendicular to the horizontal)? c) What is in Cd the intensity reading on the meter if we rotate the first polarizer by 45? relative to the horizontal? d) What is in Cd the intensity reading on the meter if we remove the second polarizer while keeping the first at 45? relative to the horizontal? e) We put back the second polarizer with its axis parallel to the horizontal. What is in Cd the intensity reading on the meter if we rotate the first polarizer by 7? relative to the horizontal?

Explanation / Answer

a)

Malus' Law:

I= Iocos^2theta

light intensity=33Cd

I=44*cos20

=44Cd

b)

in this case we will never get intensity because
meter with the axis of the polarization of the polarizer parallel to the horizontal (pond surface)

c)

I=33*(cos45)2

=33/2

=16.5 Cd

d)

I=33*(cos45)^2

=16.5Cd

e)

I=16.5*(cos13)^2

=15.665 Cd

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