4/30/2015 06:00 PM A o/10o Time Remaining 4 H27 M Gradebook Question 1 of 8 Map

Question

4/30/2015 06:00 PM A o/10o Time Remaining 4 H27 M Gradebook Question 1 of 8 Map A sapling. As you may have learned when studying the properties of thermal energy, building contractors often install windows to thermal energy Theat from entering/exiting the building Although effective as insulators, such windows present interesting optical effects In the figure, a double-glazed window comprises two identical panes of glass (ng 1.40) separated by an air gap. If the light encounters the glass at an angle of 40.00 with respect to the glass, find the shift in path Ax as the light enters the room. (Use na 1.00) 40.000 Number mm 52.0 mm glass 41.6 mm air glass 52.0 mm AO Previous Check Answer Next Exit

Explanation / Answer

We know that the shift in path will occour whenever the beam enters from air to glass i.e when it will travel in air, it will travel along the same original path angle at which it started to travel actually.
So, from the figure, we can easily guess that it will be shifted twice,both on the occasion when it enters from air to glass. Also there will be equal shift in both cases as the thickness of glass is same(52 mm) and the incident angle in both the cases will be same(40 degree).
So we will just find the shift in one case and multiply it by 2 to get the overall shift.

from snell's law, n(g)/n(a)=sin(i)/sin(r)--------i-incident angle & r- angle of refraction.
When we will convert these sin functions in terms of length, then we will find that:-
n(g)/n(a)= Apparent depth of light beam/Real depth of light beam
So, after elaborating it further, we get
k=(1-(n(a)/n(g)))* width of glass where k= Shift in path when beam enters the glass for the first time.
Solving this, we find the value of k
k= 14.85 mm.
So the net shift in path will be 2*k i.e 29.714mm.

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