1. (a) Consider an electron located in between two protons. They are all in the

Question

1. (a) Consider an electron located in between two protons. They are all in the same straight line. Calculate the net force on the electron if it is located a distance, x = 0.25 A, from one of the proton. The distance between the two protons is 1 Angstrom.

(b) What kind of a motion you expect the electron to undergo if it is held a little bit away from the center and then released?

2. (a) A force of 5 N acts on a particle making an angle 30 degrees (anti-clockwise) from the positive x-axis. What are the x, y components of the force?

(b) Suppose now you add a second force which has the same magnitude, but it makes an angle of 30 degrees (clockwise) from the negative x-axis. What is the total force acting on the particle?

3. (We now translate the above problem into a problem of electrostatics.) Two protonsarelocatedalongthex-axisatx=Landx=?L,whereL=1A. An electron lies along the y-axis, so it has coordinates (0, y). What is the direction and magnitude of the force that the electron experiences. Compute this as a function of y, and evaluate it

Explanation / Answer

a)

Here , as both the protons will attract the electron towards them

net force on electron ,

Fnet = F1 - F2

Fnet = k*e^2/(.25 *10^-10)^2 - k*e^2/((1 - .25)*10^-10)^2

now,solving for Fnet

Fnet = 3.286 *10^-7 N

Net force on the electron is 3.286 *10^-7 N

b)

as the electron is attracted by both proton,

when it is moved little bit away ,

it will start Simple Harmonic motion

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