When unpolarized light passes through a polarizing filter, A. all the light pass

Question

When unpolarized light passes through a polarizing filter,
A. all the light passes through and remains unpolarized.
B. all the light passes though and is now polarized.
C. it is completely absorbed by the filter.
D. about half the light passes through and remains unpolarized.
E. about half the light passes through and is now polarized.

When an EM wave is polarized, this means
A. The associated magnetic field is constantly changing.
B. The associated magnetic field is constantly changing.
C. The velocity of the wave is basically reduced.
D. The electric field only oscillates in one direction, in a plane perpendicular to the direction of EM wave.
E. The magnetic field oscillates in a plane perpendicular to the direction of EM wave.

Light of wavelength l = 500 nm is incident upon a double-slit arrangement in which the distance between the slits d = 1.00 x 10-3 m. On a screen a distance 1.00 m from the slits, a bright line is observed at yn = 1.50 mm from the center of the screen. What bright line is this, or in other words, what is the value of n? [hint: path diff = nl, n = 0, 1, 2

Explanation / Answer

1) Polaroid filters are made up of special material that is capable of blocking one of two planes of vibrations of electromagnetic wave. Thus Polaroid serve as a device that filters out one - half of two vibrations upon transmission of light through filters.

So ans ( E ) - about half the light passes through and now polarized.

2) The electromagnetic waves are said to be polarized when their electric field vectors are all in single plane, called the plane of oscillations.

so and - ( D ) the electric field oscillates in one direction.

3) Condition for maxima ( bright line) :

d* sin@ = n * l ( lambda-wavwlength)

also sin@ = y/ D ,              d*y/ D = n*l

n = d*y/ D*l                        ------------------------------1

d = distance between slits, y = 1.50 mm,   D = distance of screen from slits = 1m

l = wavelength = 500 nm

by putting all the values in eq. 1

n = 1*10-3 *1.50*10-3 / 1*500*10-9

n = 3

4) frequency ( f) = 100 MHz                                        ( 1 MHz = 106 Hz)

time period( T ) = 1/f

T = 1/ 100* 106

T = 10-8 sec

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