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e II H) U.S. 81% Thu 10:50 PM a Chrome File Edit View History Bookmarks People Window Help Mastering Physics: Homework #8 (Chapter 24 https:// session masteringphysics.com/ myct/itemView? assignment ProblemID 48089179 PHY 172/174 Spring 2015 He Close Homework #8 (Chapter 24 Problem 24.54 13 of 15 next previous Problem 24.54 Part A At the equator, the earth's field is essentially horizontal; In what direction should current pass through the co to produce a net field in the center of the tank that has a dip angle of 62 near the north pole, it is nearly vertical. In between, the angle varies. As you move farther north, the dip angle, clockwise the angle of the earth's field below horizontal, steadily increases. Green turtles seem to use this dip angle to counterclockwise determine their latitude. Suppose you are a researcher wanting to test this idea. You have gathered green turtle Subm My Answers Give U hatchlings from a beach where the magnetic field strength is 50 AT and the dip angle is 56 o. You then put the turtles in a 1.1 m diameter circular tank and Part B monitor the direction in which they swim as you vary the magnetic field in the tank. You change the field by What current should you pass through the co to produce a net field in the center of the tank that has a dip angle of 62 ° passing a current through a 100-turn horizontal coil cant figures and include the appropriate units. wrapped around the tank. This creates a field that adds Express your answer to two sign to that of the earth Value Units Subm My Answers Give U Continue Provide FeedbackExplanation / Answer
A) clockwise (when we see from top of the loop)
B)
Let B is the magnetic filed produced by coil.
By = B
and Bx = 0
Given, Bh = 50 micro T
Bhx = Bh*cos(56) = 50*cos(56) = 27.96 micro T
Bhy = Bh*sin(56) = 50*sin(56) = 41.45 micro T
Bnetx = 27.96 micro T
Bety = B + 41.45 micro T
tan(theta) = Bnety/Bnetx
tan(62) = (B + 41.45*10^-6)/(27.96*10^-6)
tan(62)*27.96*10^-6 = (B + 41.45*10^-6)
B + 41.45*10^-6 = 52.58*10^-6
B = (52.58-41.45)*10^-6
= 11.13*10^-6
We know, B = N*mue*I/(2*r)
==> I = B*2*r/(N*mue)
= 11.13*10^-6*2*0.55/(100*4*pi*10^-7)
= 0.10 A <<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<------------Answer
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