An eight turn coil encloses an elliptical area having a major axis of 40.0 cm an

Question

An eight turn coil encloses an elliptical area having a major axis of 40.0 cm and a minor axis of 30.0 cm (Fig. P19.23). The coil lies in the plane of the page and has a5.65 A current flowing clockwise around it. If the coil is in a uniform magnetic field of 1.91 ? 10-4 T, directed toward the left of the page, what is the magnitude of the torque on the coil? (Hint: The area of an ellipse is A = ?ab, where a and b are, respectively, the semimajor and semiminor axes of the ellipse.)

Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. N

Explanation / Answer

we are given with
   N = 8
   B = 1.91 x 10-4T
   I = 5.65 amps
   the area is
   A = ? a b
       = ? (0.200 m) (0.150m)
       = 0.09425 m2
   as from the given we can see that the field isparallel to the plane of the loop we get
   ? = 90.0o
   ? = N I A B sin?
   = (8) (5.65 amps) (0.09425) (1.91 x 10-4T)sin90o
   = 8.137 *10^-4 N.m
   the torque is directed to make the left hand side ofthe loop move toward you and the right hand
   side move away

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