An object is placed 20.0 cm from a first converging lens of focal length 11.7 cm

Question

An object is placed 20.0 cm from a first converging lens of focal length 11.7 cm. A second converging lens with focal length 5.00 cm is placed 10.0 cm to the right of the first converging lens. Find the position qi of the image formed by the first converging lens. (Enter your answer to at least two decimal places.) How far from the second lens is the image of the first lens? (Enter your answer to at least two decimal places.) What is the value of P2, the object position for the second lens? (Enter your answer to at least two decimal places.) Find the position q2 of the image formed by the second lens. (Enter your answer to at least two decimal places.) Calculate the magnification of the first lens. Calculate the magnification of the second lens. What is the total magnification for the system?

Explanation / Answer

Image due to first lense is formed at a distance 28.193 cm right to the first lense. so distance of this image from second lense will be 28.193-10 = 18.193cm

image is 18.193cm right to the second lense.

This image is right side of lense and it behave as object for second lense. By sign convension for object on right side of lense we take distance negative so it is negative.

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