please use the image to answer question 25 only Question 25 Describe this image.
ID: 1379247 • Letter: P
Question
please use the image to answer question 25 only
Question 25
Describe this image.
inverted, larger, virtual
inverted, same size, virtual
upright, larger, real
upright, smaller, real
inverted, larger, real
inverted, same size, real
upright, same size, real
upright, larger, virtual
upright, smaller, virtual
inverted, smaller, real
upright, same size, virtual
inverted, smaller, virtual
inverted, larger, virtual
inverted, same size, virtual
upright, larger, real
upright, smaller, real
inverted, larger, real
inverted, same size, real
upright, same size, real
upright, larger, virtual
upright, smaller, virtual
inverted, smaller, real
upright, same size, virtual
inverted, smaller, virtual
Real world optical systems, such as telescopes or microscopes, use multiple lenses. In the case of the two-lens system shown here: the image l1 of the object O1 generated by the first lens (L1) becomes the object O2 for the second lens (L2). The object is 40 cm from the first lens. The lenses are identical with a power of 6.67 D. To the nearest whole number, what is the focal length in centimeters of one of these lenses?Explanation / Answer
The power of lens is 6.67 D ==> f = 1/ 6.67 m = 15 cm
The thin lens equation is
1/ O1 + 1/ I1 = /1 f1
1/ I1 = 1/ 15 cm - 1/ 40 cm
I1 = 24 cm.
The object of second lens is O2 = d - I1 = 30 cm - 24 cm = 6 cm
The first image is located between F1&2 and L2
The position of final image is
1/ I2 = 1/ f2 - 1/ O2
= 1/ 15 cm - 1/ 6 cm
I2 = -10 cm
The image is virtual image .
Magnificaton is
M = ( -I1 / O1 ) ( -I2 / O2 )
= ( - 24 cm / 40 cm ) ( -( -10 cm ) / 6 cm )
= -1
Magnification is < 0, so the image is inverted.
Thus the image is inverted, same size , virtual
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.