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please use the image to answer question 25 only Question 25 Describe this image.

ID: 1379247 • Letter: P

Question

please use the image to answer question 25 only

Question 25

Describe this image.

inverted, larger, virtual

inverted, same size, virtual

upright, larger, real

upright, smaller, real

inverted, larger, real

inverted, same size, real

upright, same size, real

upright, larger, virtual

upright, smaller, virtual

inverted, smaller, real

upright, same size, virtual

inverted, smaller, virtual

inverted, larger, virtual

inverted, same size, virtual

upright, larger, real

upright, smaller, real

inverted, larger, real

inverted, same size, real

upright, same size, real

upright, larger, virtual

upright, smaller, virtual

inverted, smaller, real

upright, same size, virtual

inverted, smaller, virtual

Real world optical systems, such as telescopes or microscopes, use multiple lenses. In the case of the two-lens system shown here: the image l1 of the object O1 generated by the first lens (L1) becomes the object O2 for the second lens (L2). The object is 40 cm from the first lens. The lenses are identical with a power of 6.67 D. To the nearest whole number, what is the focal length in centimeters of one of these lenses?

Explanation / Answer

The power of lens is 6.67 D ==> f = 1/ 6.67 m = 15 cm

The thin lens equation is

1/ O1 + 1/ I1 = /1 f1

1/ I1 = 1/ 15 cm - 1/ 40 cm

I1 = 24 cm.

The object of second lens is O2 = d - I1 = 30 cm - 24 cm = 6 cm

The first image is located between F1&2 and L2

The position of final image is

1/ I2 = 1/ f2 - 1/ O2

= 1/ 15 cm - 1/ 6 cm

I2 = -10 cm

The image is virtual image .

Magnificaton is

M = ( -I1 / O1 ) ( -I2 / O2 )

= ( - 24 cm / 40 cm ) ( -( -10 cm ) / 6 cm )

= -1

Magnification is < 0, so the image is inverted.

Thus the image is inverted, same size , virtual