(33%) Problem 2: A uniform thin rod of mass m 4.8 kg and length L 1.2 m can rota
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(33%) Problem 2: A uniform thin rod of mass m 4.8 kg and length L 1.2 m can rotate about an axle through its center. Four forces are acting on it as shown in the 45 figure. Their magnitudes are F 2.5 N, F. N, F. 15 N and F 19.5 N. F2 acts a distance d 0.28 m from the center of mass Randomized Variables 60 m 4.8 kg L 1.2 m Fi 2.5 N F3 15 N Fa 19.5 N d 0.28 m. 20% Part (a) Calculate the magnitude ri of the torque due to force Fi in N.m. 20% Part (b) Calculate the magnitude t of the torque due to force F2 in N.m. A 20% Part (c) Calculate the magnitude t3 of the torque due to force F 3 in N.m A 20% Part (d) Calculate the magnitude ry of the torque due to force Fu in N.m. A 20% Part (e) Calculate the angular acceleration a of the thin rod about its center of mass in rad s2. Let the counter-clockwise direction be positive Grade Summary Deductions 0% 100% Potential sino coso tano 7 8 9 HOME Submissions Attempts remaining: 3 cotano asino acos0 4 5 6 10% per attempt atano acotano si 1 2 3 detailed viewExplanation / Answer
A) torque 1 = - 2.5*0.6 = -1.5 N.m
B) torque 2 = (F2sin(45))*0.28 = 1*sin(45)*0.28 = 0.198 N.m
C) torque 3 = 0
d) torque 4 = 0
E) net torque = I*aplha = -1.5 + 0.198 = -1.302 N.m
I = (M*L^2)/12 = (4.8*1.2^2)/12 =0.576 kg-m2
aplha = - 2.26 rad/s2
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