3. Curvature radii for charged particles in B A Li^7 nucleus has a charge equal

Question

3. Curvature radii for charged particles in B A Li^7 nucleus has a charge equal to +3qe and a mass that is equal to the mass of seven protons, mLi = 7.mp. The Li^7 nucleus and a proton are both moving perpendicular to a uniform magnetic field B. The magnitude of the momentum the proton is equal to the magnitude of the momentum of the nucleus. The path of the proton has a radius of curvature equal to Rp and the path of the Li^7 nucleus has a radius of curvature equal to RLi. Calculate the ratio Rp/RLi Solution: qvB = m v^2/R solve for R

Explanation / Answer

Here,

in the magnetic field   ,

as mv^2/R = B*q*v

R = mv/(B*q)

Now, as momentum = mv is same for both the proton and Li ,

in the same magnetic field

Rp/RLi = qLi/qe

Rp/RLi = 3*qe/qe

Rp/RLi = 3

Hence, the ratio Rp/RLi is 3

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