#21a 6 please help me (a) What is the resistance to ground of 50 of these insula

Question

#21a 6

please help me

(a) What is the resistance to ground of 50 of these insulators? (Assume the insulators are connected in parallel.)
?

(b) Calculate the power dissipated by 50 of them.
W

(c) What fraction of the power carried by the line is this?

=

P Ptotal #21a 6 please help me A 190-kV power transmission line carrying 500 A is hung from grounded metal towers by ceramic insulators, each having a1.50 x 10^9 ? resistance. (a) What is the resistance to ground of 50 of these insulators? (Assume the insulators are connected in parallel.) ? (b) Calculate the power dissipated by 50 of them. W (c) What fraction of the power carried by the line is this? P Ptotal =

Explanation / Answer

Part A)

Since Resistance in parallel is from 1/ R = 1/R1 + 1/R2 + ... we get

1/R = 50/(1.5 X 109)

R = 3.0 X 107 Ohms

Part B)

V = IR

190000 = I(3 X 107)

I = 6.33 X 10-3 Amps

P = I2R for the resistors

P = (6.33 X 10-3)2(3 X 107)

P = 1203 Watts

Part C)

P = IV for the line

P = (500)(190000)

P = 9.5 X 107 Watts

The ratio...

(1203)/(9.5 X 107) = 1.27 X 10-5 (which is .00127%)

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