The following figure shows a 2.6-cm-diameter solenoid passing through the center
ID: 1376399 • Letter: T
Question
The following figure shows a 2.6-cm-diameter solenoid passing through the center of a 5.8-cm-diameter loop. The magnetic field inside the solenoid is 0.22T .(Figure 1)
a)What is the magnetic flux through the loop when it is perpendicular to the solenoid?
flux=__________
b)What is the magnetic flux through the loop when it is tilted at a 60 ? angle?
flux=__________
The following figure shows a 2.6-cm-diameter solenoid passing through the center of a 5.8-cm-diameter loop. The magnetic field inside the solenoid is 0.22T .(Figure 1) a)What is the magnetic flux through the loop when it is perpendicular to the solenoid? flux=__________ b)What is the magnetic flux through the loop when it is tilted at a 60 ? angle? flux=__________Explanation / Answer
a) Magnetic flux = B*A
= B*pi*r^2
where r = radius of solenoid = 2.6 cm/2 = 1.3 cm = 0.013 m
B = 0.22 T
Magnetic flux = 0.22*pi*0.013^2 = 0.0001168 Wb
b) Since outer loop diameter is higher than solenoid diameter
Magnetic flux will not change , Magnetic flux = 0.0001168 Wb
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Answers )
a) 0.0001168 Wb
b) 0.0001168 Wb
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