1.A cardiac pacemaker can be affected by a static magnetic field as small as 1.7
ID: 1376148 • Letter: 1
Question
1.A cardiac pacemaker can be affected by a static magnetic field as small as 1.7 mT. How close can a pacemaker wearer come to a long, straight wire carrying 18 A?
mm
N?m
3.A proton moving freely in a circular path perpendicular to a constant magnetic field takes 1.90 ?s to complete one revolution. Determine the magnitude of the magnetic field.
T
1. A cardiac pacemaker can be affected by a static magnetic field as small as 1.7 mT. How close can a pacemaker wearer come to a long, straight wire carrying 18 A? mm 2. A copper wire is 5.00 m long and has a cross-sectional area of 2.00 ? 10^-4 m^2. This wire forms a one turn loop in the shape of square and is then connected to a battery that applies a potential difference of 0.300 V. If the loop is placed in a uniform magnetic field of magnitude 0.600 T, what is the maximum torque that can act on it? The resistivity of copper is 1.7 ? 10^-8 omegam. Nm 3. A proton moving freely in a circular path perpendicular to a constant magnetic field takes 1.90 mus to complete one revolution. Determine the magnitude of the magnetic field. TExplanation / Answer
1 ) B = uo*I/(2*pi*r)
r = (uo*I)/(2*pi*B)
r = (4*3.14e-7*18)/(2*3.14*1.7e-3)
r = 2.11 mm <<<<----------answer
2) resistance R = rho*L/A
current i = e/R = eA/rho*L
perimeter 4a = L
side of the square a = L/4
area of loop A1 = a^2 = L^/16 = 5^2/16 = 25/16 = 1.5625 m^2
max torque = i*A1*B = (e*A*A1*B)/(rho*L)
= (e*A*A1*B)/(rho*L) = (0.3*2e-4*1.5625*0.6)/(1.7e-8*5)
= 661.76 Nm <<<<----------answer
3)
Fb = Fc
q*v*B = m*v^2/r
q*B = mv/r = mw
q*B = 2*pi*m/T
B = (2*pi)/(T*q)
B = (2*3.14*1.67e-27)/(1.9e-6*1.6e-19)
B = 3.45*10^-2 T <<<<----------answer
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