Decades ago, holiday lights were wired in series, so that if one bulb in a strin

Question

Decades ago, holiday lights were wired in series, so that if one bulb in a string burned out, all the lights in the string went dark because the burned-out bulb interrupted the circuit. Today's lights are wired at least partially in parallel, so that if one light goes out, many others in the string remain lit.

Fig 1

Decades ago, holiday lights were wired in series, so that if one bulb in a string burned out, all the lights in the string went dark because the burned-out bulb interrupted the circuit. Today's lights are wired at least partially in parallel, so that if one light goes out, many others in the string remain lit. Fig 1 Part A In which circuits in (Figure 1) does one bulb burning out leave all other bulbs lit? Check all that apply. Part B In which does one bulb burning out cause one or more of the other bulbs to go out? Check all that apply.

Explanation / Answer

Answer is A and B both. Because this is compleately a parallel connection and not a single bulb is dependent on other i.e each bulb makes their own loop and so there is no relation with any other loop.

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