please help thank youYou have built a device that measures the temperature outsi

Question

please help thank youYou have built a device that measures the temperature outside and displays it on a dial as a measure of how far away from room temperature outside is. The way the dial works is that a needle with a charged ball on the end is placed between two charged parallel plates. The strength of the uniform electric field between the plates is proportional to the outside temperature. Given that the charged ball on the needle has a charge of ?2.45

please help thank youYou have built a device that measures the temperature outside and displays it on a dial as a measure of how far away from room temperature outside is. The way the dial works is that a needle with a charged ball on the end is placed between two charged parallel plates. The strength of the uniform electric field between the plates is proportional to the outside temperature. Given that the charged ball on the needle has a charge of ?2.45 µC and the needle can be represented as a string with tension 0.350 N, and is at an angle of 15°, consider the following. What is the mass of the object? g What is the magnitude of the electric field? N/C

Explanation / Answer

apply Tension T = mg sin theta

mass m = 0.35 /(9.8 sin 15)

m = 0.1379 kgs

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apply gravitationla force = Electrical force

mg sin theta = Eq cos theta

E = T tan theta/q

E = 0.35 * tan 15/(2.45e-6)

E = 3.82 *10^4 N/C

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