At time t=0s, a 15kg cannonball is located 2.0 above the fround and has an initi
ID: 1375783 • Letter: A
Question
At time t=0s, a 15kg cannonball is located 2.0 above the fround and has an initial velocity of 12m/s directly upward. the cannonball experiences a 147N downward gravitational force that the earth exerts on the ball and the resistive drag force is negligible.
a. Three students are discussing how to determine when/where the cannonball reaches its maximum height:
Student1: I think that the cannonball reaches its maximum height when its velocity is zero because this means its not moving any higher
Student2: No, I think that we can find when it reaches its maximum height by taking the derivative with respect to time of position function and set that equal to zero
Student3: wait, aren't you both essentially saying the same thing?
which of these students, if any, do you agree with? Briefly explain your reasoning
Explanation / Answer
The meaning of maximum height is, at a height where the velocity of the vertically project body has zero velocity. As velocity of the ball is zero, the ball cannot goes up further.
The time derivative position function gives the velocity. So, if the time derivative position function is zero, it means that the velocity is zero. so, the statement of student 2 is same as student 1 and both are correct. So, the statement of student 3 is also correct.
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