a uniform meter stick weighing 5.0N can rotate about a horizontal axis through i

Question

a uniform meter stick weighing 5.0N can rotate about a horizontal axis through its left end (see figure 11.3 ). A 0.15 kilogram mass is suspended 75cm from the pivoted left end and a strong holds up the right end of the meter stick. what's the tension in the string ?

a uniform meter stick weighing 5.0N can rotate about a horizontal axis through its left end (see figure 11.3 ). A 0.15 kilogram mass is suspended 75cm from the pivoted left end and a strong holds up the right end of the meter stick. what's the tension in the string ?

Explanation / Answer

Here ,

we will balance the torque about the pivot

5*0.5 + 0.15 * 9.8 * 0.75 - T*1 = 0

solving for T

T = 3.603 N

the tension in the string is 3.603 N

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